有一字符串
$content = <div id="memberflat" class="titlebar">
<div class="drawsidetow">会员平台</div>
<div class="smalltitle">为何注册?</div>
</div>
<hr />
<link rel="stylesheet" href="a/1.css" type="text/css"media="screen" />
<link rel="stylesheet" href="a/2.css" type="text/css" media="screen" />;
我怎样把$content里面的含有link的样式连接代码去掉,注意样式的地址是不定的,所以str_replace()函数实现不了
最终结果显示为:
$content = <div id="memberflat" class="titlebar">
<div class="drawsidetow">会员平台</div>
<div class="smalltitle">为何注册?</div>
</div>
<hr />;
<?php
$content = <div id="memberflat" class="titlebar">
<div class="drawsidetow">会员平台</div>
<div class="smalltitle">为何注册?</div>
</div>
<hr />
<link rel="stylesheet" href="a/1.css" type="text/css"media="screen" />
<link rel="stylesheet" href="a/2.css" type="text/css" media="screen" />;
$pattern = "/<link[^>]*>/";
$new_content = preg_replace($pattern,,$content);
?>